Tmua 2022 Paper 2 Solutions. TMUA Past Papers TutorChase Test of Mathematics for University Admission, 2022 Paper 2 Solutions Question 1 We di erentiate to obtain dy dx = 12x3 + 12x2 + 12x: We solve the equation dy dx = 0 to nd the number of stationary points: 12x3 + 12x2 + 12x= 0 if and only if 12x(x2 + x+ 1) = 0: So either x= 0 or x2 + x+ 1 = 0 Test of Mathematics for University Admission (TMUA) 2022 Paper 1 answer key 2 answer key Question Answer Question 1 C 2 D 3 F 4 4C 5 H 6 F 7 E 8 B 8 9 E 10 C 11 A 12 D 13 A 14 D 15 H 16 B 17 D 18 B 19 F 19 20 B Answer 1 B 2 E 3 C B 5 F 6 C 7 F C 9 A 10 G 11 C 12 F 13 E 14 D 15 F D 17 E 18 E B 20 E
TMUA 2020 Paper 2 Q20 Worked Solution YouTube from www.youtube.com
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TMUA 2020 Paper 2 Q20 Worked Solution YouTube
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